JEE Main & Advanced Sample Paper JEE Main Sample Paper-30

  • question_answer
    If at\[298\,K,\]the solubility of \[AgCl\] in \[0.05M\]\[BaC{{l}_{2}}\] (completely dissociated) is found to be very nearly \[{{10}^{-9}}M\]and\[E_{Ag/A{{g}^{+}}}^{0}=-\,0.80\,V\]. Then the value of \[E_{C{{l}^{-}}/AgCl/Ag}^{0}\] at the same temperature will be:

    A) \[1.39\,V\]                               

    B) \[0.829\,V\]

    C) \[-\,0.7705\,V\]

    D) \[0.21\,V\]

    Correct Answer: D

    Solution :

    \[{{K}_{sp}}\]for \[AgCl={{10}^{-9}}\times (0.1)={{10}^{-10}}\] \[\therefore \,E_{C{{l}^{-}}/AgCl/Ag}^{0}=+0.80+\frac{0.059}{1}{{\log }^{{{10}^{-10}}}}\] \[=0.21\,V\]


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