A) 10
B) \[\frac{70}{11}\]
C) 7
D) 5
Correct Answer: A
Solution :
The first line is \[\frac{x-1}{-3}=\frac{y-2}{2p/7}=\frac{z-3}{2};\] parallel \[{{\overrightarrow{v}}_{1}}=-3\widehat{i}+\frac{2p}{7}\widehat{j}+2\widehat{k}\]\[1+ba>0\] Second line \[\frac{(x-1)}{-3p/7}=\frac{y-5}{-1}=\frac{z-6}{-5};\] parallel to \[{{\overrightarrow{v}}_{2}}=\frac{3p}{7}\widehat{i}-\widehat{j}-5\widehat{k}\] Now, \[-3.\left( \frac{-3p}{7} \right)+\left( \frac{2p}{7} \right).(-1)+2(-5)=0\] \[\therefore 7p=70\Rightarrow p=10\]You need to login to perform this action.
You will be redirected in
3 sec