A) 0
B) 1
C) 2
D) 3
Correct Answer: A
Solution :
\[\frac{ydx-xdy}{{{y}^{2}}}=\frac{-ydy}{{{y}^{2}}}\Rightarrow \int{{}}d\left( \frac{x}{y} \right)\] \[=\int{{}}\frac{-dy}{y}\Rightarrow \frac{x}{y}+\ell ny=C\] As, A(0, 1) lies on it, so \[0+0=C\Rightarrow C=0\] \[\therefore \frac{x}{y}+\ell ny=0\] ?(i) Put \[y=e\] in (1), we get \[\frac{x}{e}\ell ne=0\Rightarrow x=-e\] \[\therefore (a=-e,\,\,b=e)\] Hence, \[(a+b)=0\]You need to login to perform this action.
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