A) \[\frac{967}{1024}\]
B) \[\frac{957}{1024}\]
C) \[\frac{964}{1024}\]
D) \[\frac{977}{1024}\]
Correct Answer: B
Solution :
\[n=10;\,\,p=\frac{1}{2};\,\,q=\frac{1}{2}\] \[P(3\le r\le 8)=1-P(0)+P(1)+P(2)+P(9)+P(10)]\]\[=1-\frac{1}{{{2}^{10}}}{{[}^{10}}{{C}_{0}}{{+}^{10}}{{C}_{1}}{{+}^{10}}{{C}_{2}}{{+}^{10}}{{C}_{9}}{{+}^{10}}{{C}_{10}}]\] \[=1-\frac{1}{{{2}^{10}}}[2+20+45]\] \[=1-\frac{67}{1024}=\frac{1024-67}{1024}=\frac{957}{1024}\]
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