A) a circle
B) a parabola
C) an ellipse
D) a hyperbola
Correct Answer: C
Solution :
\[\therefore \,\,h=\frac{a\,\,\cos \,\theta }{3}\Rightarrow \,\cos \,\theta =\frac{3h}{a}\] \[k=\frac{b\,\sin \,\theta }{3}\Rightarrow \,\sin \,\theta \,=\frac{3k}{b}\] \[\therefore \,\,\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=\frac{1}{9}\](ellipse)You need to login to perform this action.
You will be redirected in
3 sec