A) \[\frac{{{e}^{1/2}}}{{{e}^{1/2}}-1}\]
B) \[\frac{{{e}^{2}}}{{{e}^{2}}-1}\]
C) \[1-{{e}^{-1}}\]
D) \[{{e}^{-1}}\]
Correct Answer: B
Solution :
\[i=\,\frac{V}{R}(1-e{{\,}^{-\frac{tR}{L}}})\] \[\frac{{{i}_{\infty }}\,=1.5}{{{i}_{i}}=1.5\,(1-{{e}^{-2}})}\,=\frac{{{e}^{2}}}{{{e}^{2}}-1}\]You need to login to perform this action.
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