A) \[0.1\,s\]
B) \[0.4\,s\]
C) \[0.2\,s\]
D) \[0.8\,s\]
Correct Answer: B
Solution :
\[{{t}_{1/2}}\propto \,{{(a)}^{1-a}}\] \[\frac{{{({{t}_{1/2}})}_{1}}}{{{({{t}_{1/2}})}_{11}}}\,={{\left( \frac{{{a}_{1}}}{{{a}_{2}}} \right)}^{1-0}}\] \[\frac{0.2}{{{\left( {{t}_{1/2}} \right)}_{1}}}=\frac{{{A}_{0}}}{2{{A}_{0}}}\] \[{{({{t}_{1/2}})}_{11}}=0.4\,s\]
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