A) \[{{W}_{1}}>{{W}_{2}}={{W}_{3}}\]
B) \[{{W}_{2}}<{{W}_{1}}<{{W}_{3}}\]
C) \[{{W}_{1}}<{{W}_{2}}={{W}_{3}}\]
D) \[{{W}_{1}}<{{W}_{2}}<{{W}_{3}}\]
Correct Answer: D
Solution :
The power \[{{B}_{3}}\] is \[{{W}_{3}}=60\,W\] The combined power of \[{{B}_{1}}\] and \[{{B}_{2}}\] is \[{{W}_{1}}+{{W}_{2}}=\frac{100\times 60}{100+60}=37.5W\] The current through \[{{B}_{1}}\] and \[{{B}_{2}}\] is same as they are in series. Since, \[{{B}_{2}}\] has more resistance\[{{W}_{1}}<{{W}_{2}}\]. \[\therefore \,\,{{W}_{1}}<{{W}_{2}}<{{W}_{3}}\]
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