A) Length \[=50\,cm\], diameter \[=0.5\,mm\]
B) Length \[=100\,cm\], diameter \[=1\,\,mm\]
C) Length \[=200\,cm\], diameter \[=2\,\,mm\]
D) Length \[=300\,cm\], diameter \[=3\,\,mm\]
Correct Answer: A
Solution :
\[\Delta L\,=\frac{FL}{(\pi {{d}^{2}}/4)Y}\] \[\Delta L\,\propto \,\frac{L}{{{d}^{2}}}\] In option (1) \[\frac{L}{{{d}^{2}}}\] is maximum
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