A) \[\frac{4\pi {{\varepsilon }_{0}}abd}{(b-a)(d-b)}\]
B) \[\frac{4\pi {{\varepsilon }_{0}}ab}{(b-a)}\]
C) \[\frac{4\pi {{\varepsilon }_{0}}ab}{(d-b)}\]
D) \[\frac{4\pi {{\varepsilon }_{0}}ad}{(d-a)}\]
Correct Answer: C
Solution :
\[{{E}_{r}}=\frac{q}{4\pi {{\varepsilon }_{0}}{{r}^{2}}}\] \[-\int_{b}^{d}{dV=\frac{q}{4\pi {{\varepsilon }_{0}}\,{{r}^{2}}}\,\int_{b}^{d}{\frac{dr}{{{r}^{2}}}}}\] Or \[{{V}_{b}}-{{V}_{a}}=\frac{q}{4\pi {{\varepsilon }_{0}}}\,\frac{(d-b)}{bd}\] Or \[C=\frac{4\pi {{\varepsilon }_{0}}bd}{(d-b)}\]You need to login to perform this action.
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