A) Metal excess
B) Metal deficiency
C) Impurities
D) None of these
Correct Answer: A
Solution :
\[ZnO\xrightarrow{heat}Z{{n}^{2+}}+\frac{1}{2}{{O}_{2}}+2{{e}^{-}}\] Excess \[Z{{n}^{2+}}\] ions are trapped by vacant interstitial sites and the electrons are in neighbouring interstitial sites.You need to login to perform this action.
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