A) \[\infty \]
B) zero
C) \[C[\sqrt{3}-1)/2]\]
D) \[C[\sqrt{3}+1)/2]\]
Correct Answer: C
Solution :
\[\frac{1}{{{C}_{\infty }}}=\frac{1}{{{C}_{\infty }}+C}+\frac{2}{C}=\frac{3C+2{{C}_{\alpha }}}{{{C}_{\alpha }}({{C}_{\alpha }}+C)}\]\[2{{C}_{\infty }}^{2}+2C{{C}_{\infty }}-{{C}^{2}}=0\to {{C}_{\infty }}=C\left( \frac{-1+\sqrt{3}}{2} \right)\]
You need to login to perform this action.
You will be redirected in
3 sec
