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JEE Main & Advanced Sample Paper JEE Main Sample Paper-39

  • question_answer
    Two waves of wavelengths 99 cm and 100 cm both travelling with velocity 396 m/s are made to interfere. The number of beats produced by them per second are

    A)  1                                

    B)  2

    C)  4                                

    D)  8

    Correct Answer: C

    Solution :

     Velocity of wave \[v=n\lambda \]where n = frequency of wave \[\Rightarrow n=\frac{v}{\lambda }\] \[{{n}_{1}}=\frac{{{v}_{1}}}{{{\lambda }_{1}}}=\frac{396}{99\times {{10}^{-2}}}=400Hz\] \[{{n}_{2}}=\frac{{{v}_{2}}}{{{\lambda }_{2}}}=\frac{396}{100\times {{10}^{-2}}}=396Hz\] No. of beats\[={{n}_{1}}-{{n}_{2}}=4\]


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