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JEE Main & Advanced Sample Paper JEE Main Sample Paper-3

  • question_answer
    An alternating voltage E(in volt) \[200\sqrt{2}\]sin 100 t is connected to one microfarad capacitor through an A.C. ammeter. The reading of the ammeter shall be

    A)  \[20\sqrt{2}\,mA\]                        

    B)  20 mA

    C)  40 mA                 

    D)  80 mA

    Correct Answer: B

    Solution :

     \[{{X}_{C}}=\frac{1}{\omega C};{{E}_{rms}}=\frac{{{E}_{0}}}{\sqrt{2}};\] \[{{E}_{0}}=200\sqrt{2};{{E}_{rms}}=200;\] \[{{X}_{C}}=\frac{1}{\omega C}=\frac{1}{100\times {{10}^{-6}}}={{10}^{4}}\Omega \] \[V=IR\]or\[\frac{200}{{{10}^{4}}}=I=20mA\]


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