A) \[3\times {{10}^{-3}}M\]
B) \[7\times {{10}^{-2}}M\]
C) \[2.89\times {{10}^{-4}}M\]
D) \[2\times {{10}^{-2}}M\]
Correct Answer: D
Solution :
The maximum concentration of \[S{{O}_{4}}^{-2}\] will be same as the solubility of\[{{M}_{2}}S{{O}_{4}};\] If solubility is \[{{L}^{-1}}mol\,{{L}^{-1}}{{M}_{2}}S{{O}_{4}}2{{M}^{+}}+S{{O}_{4}}^{-2}\] \[{{K}_{sp}}=4{{x}^{3}},\]therefore \[x={{({{K}_{sp}}/4)}^{1/3}}\] \[[S{{O}_{4}}^{-2}]=x={{({{K}_{sp}}/4)}^{1/3}}=[3.2\times {{10}^{-5}}]/4{{]}^{1/3}}\] \[=2\times {{10}^{-2}}M\]You need to login to perform this action.
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