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JEE Main & Advanced Sample Paper JEE Main Sample Paper-41

  • question_answer
    A box contains 100 tickets numbered only one maximum 1, 2, ...,100. Two tickets are chosen at random.         It is given that the maximum number on the t two chosen tickets is not more than 10. Then, the probability that the minimum number on them is 5, is                                        

    A)  \[\frac{13}{14}\]                               

    B)  \[\frac{1}{9}\]

    C)  \[\frac{12}{15}\]                               

    D)  None of these

    Correct Answer: B

    Solution :

    Required probability \[=\frac{^{5}{{C}_{1}}}{^{10}{{C}_{2}}}=\frac{1}{9}\] (Since, in the chosen tickets one number is 5 and the rest of the numbers may be 6, 7, 8, 9, 10.)      


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