question_answer

Current passes through a solution of sodium chloride. In \[1.00\text{ }s,2.68\times {{10}^{16}}\] ions arrive at the negative electrode and 3.92 x 1016 \[\text{C}{{\text{l}}^{-}}\] ions arrive at positive electrode. Determine the current and the direction in which it is flowing.

A)  1.056 mA, positive to negative electrode

B)  10.56 mA, positive to negative electrode

C)  1.056 mA, negative to positive electrode

D)  10.56 mA, negative to positive electrode

Correct Answer: B

Solution :

Current\[=\frac{q}{t}=\frac{[{{n}_{N{{a}^{+}}}}+{{n}_{C{{l}^{-}}}}]e}{t}\] \[=\frac{(2.68\times {{10}^{16}}+3.92\times {{10}^{16}})(1.6\times {{10}^{-19}})}{1.00}\] =10.56 mA Direction of current is from positive electrode to negative electrode as Na+ are positively charged while Cl- are negatively charged.