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JEE Main & Advanced Sample Paper JEE Main Sample Paper-41

  • question_answer
    At \[20{}^\circ C\] and 1.00 atm partial pressure of hydrogen, 18 mL of hydrogen, measured at STP, dissolves in 1L of water. If water at \[20{}^\circ C\] is exposed to a gaseous mixture having a total pressure of 1400 Torr (excluding the vapour pressure of water) and containing 68.5% \[{{\text{H}}_{\text{2}}}\] by volume, find the volume of H2, measured at STP, which will dissolve in 1L of water.

    A)  18 mL                        

    B)  12 mL

    C)  23 mL                        

    D)  121 mL

    Correct Answer: C

    Solution :

    \[p({{H}_{2}})=(1400Torr)(0.685)\] \[=959Torr\equiv 959/760atm=1.26atm\] According to Henry's law "Amount of gas absorbed is directly proportional to pressure." Hence \[\frac{V}{18mL}=\frac{1.26atm}{1atm}\]\[V=23mL\]


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