JEE Main & Advanced Sample Paper JEE Main Sample Paper-42

  • question_answer
    The chemical reaction \[2{{O}_{3}}\to 3{{O}_{2}}\] proceeds as follows \[{{O}_{3}}{{O}_{2}}+O\] .... (fast)\[O+{{O}_{3}}\to 2{{O}_{2}}\].... (slow), the rate law expression should be

    A) \[r=k{{[{{O}_{3}}]}^{2}}\]                     

    B) \[r=k{{[{{O}_{3}}]}^{2}}{{[{{O}_{2}}]}^{-1}}\]

    C) \[r=k[{{O}_{3}}][{{O}_{2}}]\]     

    D)  un predictable

    Correct Answer: B

    Solution :

    \[K=\frac{[{{O}_{2}}][O]}{[{{O}_{3}}]};[O]=\frac{K[{{O}_{3}}]}{[{{O}_{2}}]}\]             ?(i) \[O+{{O}_{3}}\xrightarrow[{}]{slow}2{{O}_{2}}\] Rate \[=K[{{O}_{3}}][O]\]                           ?(ii) Frome Eqs. (i) and (ii) Rate \[=K{{[{{O}_{3}}]}^{2}}{{[{{O}_{2}}]}^{-1}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner