A) 8 m/s (approx)
B) 800 m/s
C) 7 m/s
D) 6 m/s (approx)
Correct Answer: A
Solution :
By Doppler's formula \[\phi '\] \[\tan \,\phi =\frac{V}{{{H}^{.}}}=\frac{V}{H\,\cos \,\theta }\] \[\frac{\tan \,\phi '}{\tan \,\phi }=\frac{V/H\,\cos \,\theta }{\frac{V}{H}}=\frac{1}{\cos \,\theta }\] Now adding 1 to both the sides. \[{{\phi }_{1}}=\] \[=BA\] or \[{{\phi }_{2}}=\] or \[||\]
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