• # question_answer In figure, if the surfaces are frictionless, the ratio ${{T}_{1}}:{{T}_{2}}$ is A)  $\sqrt{3}:2$               B)  $1:\sqrt{3}$ C)  1 : 5                            D)  5 : 1

Let the common acceleration of the system of masses is a Then, for mass 12 kg  $0=v-at$                               ...(i) And for the mass 3 kg $\therefore$                            ...(ii) Put the value of $-a=\frac{0-v}{t}=-\frac{v}{t}$ from Eq. (ii), in $f=\mu R=\mu mg$ (i) $a=\mu g$ $\therefore$    $t=\frac{v}{a}=\frac{v}{g\mu }$ $\eta =\frac{{{P}_{0}}}{{{P}_{i}}}$       $\therefore$