• # question_answer A reactant  forms two products $A\xrightarrow{{{k}_{1}}}B$ Activation energy ${{E}_{{{a}_{1}}}}$ $A\xrightarrow{{{k}_{2}}}C$ Activation energy $E{{\,}_{{{a}_{2}}}}$ If ${{E}_{{{a}_{2}}}}=2{{E}_{{{a}_{1}}}},$ then ${{k}_{1}}$ and ${{k}_{2}}$ will be related as A)  ${{k}_{2}}={{k}_{1}}{{e}^{-{{E}_{{{a}_{1}}}}/RT}}$     B)  ${{k}_{2}}={{k}_{1}}{{e}^{-{{E}_{{{a}_{2}}}}/RT}}$ C) ${{k}_{1}}={{k}_{2}}{{e}^{-{{E}_{{{a}_{1}}}}/RT}}$      D)  ${{k}_{1}}=2{{k}_{2}}{{e}^{{{E}_{{{a}_{2}}}}/RT}}$

$\theta ={{45}^{o}}$ $n'=\frac{v}{v-{{v}_{s}}}\times n$ $\Rightarrow$ (Since, $\frac{n'}{n}=\frac{v}{v-{{v}_{s}}}$)