A) one-one and onto
B) one-one but not onto
C) onto but not one-one
D) neither one-one nor onto
Correct Answer: A
Solution :
We have, \[\tan \theta =\frac{r}{h/2}\] \[\theta ={{45}^{o}},\] for all \[r=\frac{h}{2}\] \[\theta ={{45}^{o}}\] \[n'=\frac{v}{v-{{v}_{s}}}\times n\] is strictly increasing. \[\Rightarrow \] \[\frac{n'}{n}=\frac{v}{v-{{v}_{s}}}\] is one-one
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