A) 1
B) \[\alpha \]
C) \[{{\alpha }^{2}}\]
D) \[{{\alpha }^{3}}\]
Correct Answer: D
Solution :
Given, \[\frac{\Delta n}{n}=\frac{{{v}_{s}}}{v-{{v}_{s}}}\] and \[\frac{2.5}{100}=\frac{{{v}_{s}}}{320-{{v}_{s}}}=\frac{1}{40}\] \[40{{v}_{s}}=320-{{v}_{s}}\] \[{{v}_{s}}=\frac{320}{41}\simeq 8\,m/s\] \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\left[ \frac{Q}{R} \right]+\frac{1}{4\pi {{\varepsilon }_{0}}}\left[ \frac{q}{r} \right]\] \[=\frac{1}{{{\varepsilon }_{0}}}\left[ \frac{Q}{4\pi {{R}^{2}}}\times R+\frac{q}{4\pi {{r}^{2}}}\times r \right]\] \[\frac{Q}{4\pi {{R}^{2}}}=\frac{q}{4\pi {{r}^{2}}}=\sigma \] \[\therefore \] \[V=\frac{1}{{{\varepsilon }_{0}}}\,[\sigma R+\sigma r]=\frac{\sigma }{{{\varepsilon }_{0}}}[R+r]\]
You need to login to perform this action.
You will be redirected in
3 sec
