• # question_answer A bomb is dropped from an aeroplane when it is at a height h directly above the target. If the aero plane is moving horizontally at a speed v, the distance by which bomb will miss the target is given by A)  $2v\sqrt{\frac{h}{g}}$                     B)  $v\sqrt{\frac{h}{g}}$ C)  $v\sqrt{\frac{2h}{g}}$         D)  $v\sqrt{\frac{h}{2g}}$

As the bomb is released directly above the target, the distance by which the bomb will miss the target must be equal to its horizontal range, i.e., $\Delta x=(SA+AP)-SP$