A) \[\frac{d}{D}h\]
B) \[\left( \frac{d}{D}-1 \right)h\]
C) \[h\]
D) Zero
Correct Answer: B
Solution :
Let the volume of the ball be V. Force on the ball due to up thrust = Vdg Net upward force \[=Vdg-VDg\] Consider the force of bouyancy \[\therefore \] Upward acceleration is given by \[VDa=Vdg-VDg\] \[\therefore \] \[a=\left( \frac{d-D}{D} \right)g\] Velocity on reaching the surface, \[v=\sqrt{2ah}\] Further, \[v=\sqrt{2gH}\] \[\therefore \] \[2ah=2gH\] or \[H=\frac{ah}{g}=\,\left( \frac{d-D}{D} \right)h=\left( \frac{d}{D}-1 \right)h\]You need to login to perform this action.
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