A) 11%
B) 10%
C) 100%
D) 110%
Correct Answer: B
Solution :
\[\frac{{{p}_{1}}}{{{T}_{1}}}=\frac{{{p}_{2}}}{{{T}_{2}}}\] \[\frac{p}{260}=\frac{{{p}_{2}}}{286}\] \[1.1p={{p}_{2}}\] \[\therefore \] % increase \[=\frac{1.1\,p-p}{p}=\frac{0.1\,p}{p}\times 100=10%\]You need to login to perform this action.
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