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JEE Main & Advanced Sample Paper JEE Main Sample Paper-44

  • question_answer
    Equal masses of ethane and hydrogen are mixed in an empty container at \[25{}^\circ C\]. The fraction of the total pressure exerted by hydrogen is

    A)  1 : 2                           

    B)  1 : 1            

    C)  1 : 16                         

    D)  15 : 16

    Correct Answer: D

    Solution :

     Let the mass of ethane = hydrogen \[=x\,g\] \[\therefore \]    Moles of ethane \[=\frac{x}{30}\]and moles of hydrogen \[=\frac{x}{2}\] \[\therefore \] \[{{p}_{{{H}_{2}}}}=\frac{\frac{x}{2}}{\frac{x}{2}+\frac{x}{30}}\times {{p}_{total}}=\frac{1}{2}\times \frac{30}{16}p=\frac{15}{16}p\]


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