• # question_answer In an adsorption experiment, a graph between $\log \frac{x}{m}$ versus log p was found to be linear with a slope of ${{45}^{o}}$. The intercept on the $\log \frac{x}{m}$ axis was found to be 0.30103. Calculate the amount of the gas adsorbed per gram of charcoal under a pressure 1 atm. $[{{\log }_{10}}2=0.301032]$ A)  1                                 B)  2 C)  4                                 D)  0

$\because$    $\log \,\frac{x}{m}=\log \,k+\frac{1}{n}\,\log \,p$ $(y=c+mx$ form ) $\frac{1}{n}=\tan \,{{45}^{o}}=1$ $\log \,k=0.30103$ $\therefore$    $k=2$ $\therefore$    $\frac{x}{m}=k{{p}^{1/n}}=2\times {{1}^{1/1}}=2$