A) 100
B) 300
C) 800
D) 400
Correct Answer: C
Solution :
Let the bond dissociation energies of AB, \[{{A}_{2}}\] and \[{{B}_{2}}\], be\[x,\,\,x\] and \[0.5\,\,x\] respectively. \[\frac{1}{2}{{A}_{2}}+\frac{1}{2}{{B}_{2}}\to AB;\] \[{{\Delta }_{f}}H=-200\,\,kJ/mol\] \[\Delta H=\frac{1}{2}\,\Delta H({{A}_{2}})+\frac{1}{2}\,\Delta H({{B}_{2}})-\Delta H(AB)\] \[-200=\frac{1}{2}x+\frac{0.5x}{2}-x\]\[x=800\,\,kJ/mol\]You need to login to perform this action.
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