A) 40 min
B) 36 min
C) 12 min
D) 340 min
Correct Answer: B
Solution :
Energy of 1 mole of photon\[=\frac{{{N}_{0}}hc}{\lambda }\] \[=\frac{6.023\times {{10}^{23}}\times 6.626\times {{10}^{-34}}\times 3\times {{10}^{8}}}{560\times {{10}^{-9}}}\]\[=213.69\times {{10}^{3}}\,J\] Time taken for this energy \[=\frac{213.69\times {{10}^{3}}\,J}{100\,J{{s}^{-1}}}=2137\,s=36\,\min \]You need to login to perform this action.
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