JEE Main & Advanced Sample Paper JEE Main Sample Paper-47

  • question_answer
    A constant potential difference between A and B is applied. When the switch is shifted from position P to position Q, then

    A)  charge on \[2\mu F\] capacitor is approximately\[13\mu C\]

    B)  potential difference across \[3\mu C\]capacitor is approximately 4.3 V 

    C)  potential difference across \[1\mu F\] capacitor is approximately 11 V

    D)  All of the above

    Correct Answer: D

    Solution :

     Initially,           \[{{Q}_{1}}=24\mu \,C\] Finally, \[{{V}_{C}}=\frac{24}{\frac{6}{5}+1}=\frac{24\times 5}{11}\,volt\] \[Q_{3}^{'}=Q_{2}^{'}=\frac{6}{5}\times \frac{24\times 5}{11}13\mu \,C\]  (approx) \[Q_{1}^{'}=1\times \frac{24\times 5}{11}=1\,\,1\mu \,C\]                      (approx) \[V_{1}^{'}=11\] volt \[V_{3}^{'}=\frac{Q_{3}^{'}}{{{C}_{3}}}=\frac{13}{3}=4.3\,\] volt                       (approx)

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