• # question_answer A black colored compound [a] in solid state is fused with, $KOH$and $KCl{{O}_{3}}$and the mixture is extracted with water to obtain a green colour solution [b]. On passing $C{{O}_{2}}$through the solution the colour changes to pink with black residue [c]. Which of the following is/are correct? A)  The pink colour is decolorized by acidified $FeS{{O}_{4}}$ solution B)  The black residue [c] is same as compound [a] C)  When ${{O}_{3}}$ gas is passed through the green colour solution, it changes to pink D)  All of the above

Solution :

$\underset{\begin{smallmatrix} Black\,solid \\ A \end{smallmatrix}}{\mathop{3Mn{{O}_{2}}}}\,+6KOH+KCI{{O}_{3}}\xrightarrow[\begin{smallmatrix} + \\ extraction \\ with\,\,water \end{smallmatrix}]{Fusion}$ $\underset{\text{Green}\,\,\text{mass}}{\mathop{3{{K}_{2}}Mn{{O}_{4}}}}\,+KCl+3{{H}_{2}}O$ $\underset{\text{From}\,\,\text{Green}\,\,\text{solution}}{\mathop{3{{K}_{2}}Mn{{O}_{4}}}}\,+2{{H}_{2}}O+4C{{O}_{2}}\xrightarrow{\,}$ $2KMn{{O}_{4}}+\underset{(C)}{\mathop{Mn{{O}_{2}}}}\,+4KHC{{O}_{3}}$ $2{{K}_{2}}Mn{{O}_{4}}+{{O}_{3}}+{{H}_{2}}O\xrightarrow{\,}\,2KMn{{O}_{4}}$ $+2KOH+{{O}_{2}}$ $\underset{Pink}{\mathop{2KMn{{O}_{4}}}}\,+B{{H}_{2}}S{{O}_{4}}+10FeS{{O}_{4}}\xrightarrow{\,}$ $2MnS{{O}_{4}}+{{K}_{2}}S{{O}_{4}}$ $+5F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+8{{H}_{2}}O$

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