| (i) \[{{[Fe{{(CN)}_{6}}]}^{4-}}\] |
| (ii) \[{{[Fe{{(CN)}_{6}}]}^{3-}}\] |
| (iii) \[{{[Cr{{(N{{H}_{3}})}_{6}}]}^{3+}}\] |
| (iv) \[{{[Ni{{({{H}_{2}}O)}_{6}}]}^{2+}}\] |
A) I < II < III < IV
B) IV < III < II < I
C) II < III < I < IV
D) I < II < IV < III
Correct Answer: D
Solution :
Magnetic moment \[\propto \] number of unpaired electrons Number of unpaired electrons in the below species are (I) \[{{[Fe{{(CN)}_{6}}]}^{4-}}=0;\] (II) \[{{[Fe{{(CN)}_{6}}]}^{3-}}=1\] (III) \[{{[Cr(N{{H}_{6}})]}^{3+}}=3;\] (IV) \[{{[Ni{{({{H}_{2}}O)}_{6}}]}^{2+}}=2\] Hence, the correct order is I < II < IV < III
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