• question_answer If the areas of I-H hysteresis loop and B-H hysteresis loop are ${{A}_{1}}\And {{A}_{2}}$ respectively, then A) ${{A}_{2}}={{\mu }_{0}}{{A}_{1}}$                         B) ${{A}_{2}}={{A}_{1}}$ C) ${{A}_{2}}=\frac{{{A}_{1}}}{{{\mu }_{0}}}$                         D) ${{A}_{2}}={{\mu }_{0}}^{2}{{A}_{1}}$

We know $\vec{B}={{\mu }_{0}}(\vec{H}+\vec{l})$ $\Rightarrow$$dB={{\mu }_{0}}dH+{{\mu }_{0}}dl$ $\oint{\vec{H}.d\vec{B}={{\mu }_{0}}}\oint{\vec{H}.d\vec{H}+{{\mu }_{0}}}\oint{\vec{H}.d\vec{l}}$ $\Rightarrow$$\oint{\vec{H}.d\vec{B}={{\mu }_{0}}}\oint{Hdl}$$\Rightarrow$${{A}_{2}}={{\mu }_{0}}{{A}_{1}}$