JEE Main & Advanced Sample Paper JEE Main Sample Paper-4

  • question_answer
    Two travelling waves\[{{y}_{1}}=A\sin [k(x+ct)]\] \[{{y}_{2}}=A\sin [k(x+ct)]\]are superposed on a string. The distance between adjacent nodes is

    A) \[\frac{ct}{\pi }\]                                             

    B) \[\frac{ct}{2\pi }\]

    C) \[\frac{\pi }{2K}\]                                            

    D) \[\frac{\pi }{K}\]

    Correct Answer: D

    Solution :

    Distance between two adjacent nodes is \[\frac{\lambda }{2}=\frac{2\pi /k}{2}=\pi /k\]

You need to login to perform this action.
You will be redirected in 3 sec spinner