question_answer

In the circuit shown the current in \[3\Omega \]resistor is

A)  1A                                         

B) \[\frac{30}{7}A\]

C) \[\frac{5}{7}A\]                                

D)  Information insufficient

Correct Answer: C

Solution :

Apply KCL at junction having potential V \[\frac{V-10}{2}+\frac{V-0}{6}+\frac{V-0}{2}=0\]\[\Rightarrow \]\[V=30/7volt\] Both\[3\Omega \]resistors are connected in series, so required current \[i=\frac{V-0}{6}=\frac{5}{7}amp\]