A) 480nm
B) 530 nm
C) 650 nm
D) 580 nm
Correct Answer: B
Solution :
For maxima, \[\Delta x=n\lambda \]\[\Rightarrow \]\[\frac{dy}{D}=n\lambda \] For fourth maxima, n = 4 \[\frac{dy}{D}=4\lambda \Rightarrow \lambda =\frac{dy}{4D}=\frac{0.016\times {{10}^{-2}}\times 1.06\times {{10}^{-2}}}{4\times 0.8}\] \[\Rightarrow \lambda =530nm\]You need to login to perform this action.
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