A) \[C{{a}_{3}}{{(P{{O}_{4}})}_{2}}\]
B) \[Ca{{(OH)}_{2}}\]
C) \[N{{a}_{2}}C{{O}_{3}}\]
D) \[NaOCl\]
Correct Answer: B
Solution :
\[Ca{{(OH)}_{2}}+Ca{{(HC{{O}_{3}})}_{2}}\to 2CaC{{O}_{3}}\downarrow +\underset{(Clark's\,method)}{\mathop{2{{H}_{2}}O}}\,\]Z\[NaOH+{{H}_{2}}\to NaOH+HOCl\] \[H{{O}^{-}}+HCO_{3}^{-}\to CO_{3}^{2-}+{{H}_{2}}O\] \[Ca{{(HC{{O}_{3}})}_{2}}+N{{a}_{2}}C{{O}_{3}}\to CaC{{O}_{3}}\downarrow +2NaHC{{O}_{3}}\]
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