• question_answer What is the decreasing order of strength of the bases? $O{{H}^{-}},NH_{2}^{-},H-C\equiv {{C}^{-}}$and$C{{H}_{3}}-C{{H}_{2}}^{-}$ A) $C{{H}_{3}}-CH_{2}^{-}>NH_{2}^{-}>H-C\equiv {{C}^{-}}>O{{H}^{-}}$ B) $H-C\equiv {{C}^{-}}>C{{H}_{3}}-CH_{2}^{-}>NH_{2}^{-}>O{{H}^{-}}$ C) $O{{H}^{-}}>NH_{2}^{-}>H-C\equiv {{C}^{-}}>C{{H}_{3}}-CH_{2}^{-}$ D) $NH_{2}^{-}>H-C\equiv {{C}^{-}}>O{{H}^{-}}>C{{H}_{3}}-CH_{2}^{-}$

$C{{H}_{3}}CH_{2}^{-}>NH_{2}^{-}>H-C\equiv {{C}^{-}}>H{{O}^{-}}$ It is because the order of acid - strength of their conjugate acid is$C{{H}_{3}}C{{H}_{3}}<N{{H}_{3}}<H-C$$\equiv C-H<{{H}_{2}}O:$ Acid strength.