• # question_answer The expression to compute molar mass of a solute from the elevation of boiling point of a solvent is (where the various sybols have their usual meanings) A) ${{M}_{2}}=\frac{{{K}_{b}}}{\Delta {{T}_{b}}}\frac{{{m}_{1}}}{{{m}_{2}}}$           B) ${{M}_{2}}=\frac{\Delta {{T}_{b}}}{{{K}_{b}}}\frac{{{m}_{2}}}{{{m}_{1}}}$ C) ${{M}_{2}}=\frac{{{K}_{b}}}{\Delta {{T}_{b}}}\frac{{{m}_{2}}}{{{m}_{1}}}$           D) ${{M}_{2}}=\frac{\Delta {{T}_{b}}}{{{K}_{b}}}\frac{{{m}_{1}}}{{{m}_{2}}}$

$\Delta {{T}_{b}}={{K}_{b}}\times m={{K}_{b}}\times \frac{{{m}_{2}}}{{{M}_{2}}}\times \frac{1}{{{m}_{1}}}$where ${{m}_{2}}$is mass of solute ${{m}_{1}}$ is mass of solvent ${{M}_{2}}$ molar mass of solute${{M}_{2}}=\frac{{{K}_{b}}\times {{m}_{2}}}{\Delta {{T}_{b}}{{m}_{1}}}$