A) \[{{M}_{2}}=\frac{{{K}_{b}}}{\Delta {{T}_{b}}}\frac{{{m}_{1}}}{{{m}_{2}}}\]
B) \[{{M}_{2}}=\frac{\Delta {{T}_{b}}}{{{K}_{b}}}\frac{{{m}_{2}}}{{{m}_{1}}}\]
C) \[{{M}_{2}}=\frac{{{K}_{b}}}{\Delta {{T}_{b}}}\frac{{{m}_{2}}}{{{m}_{1}}}\]
D) \[{{M}_{2}}=\frac{\Delta {{T}_{b}}}{{{K}_{b}}}\frac{{{m}_{1}}}{{{m}_{2}}}\]
Correct Answer: C
Solution :
\[\Delta {{T}_{b}}={{K}_{b}}\times m={{K}_{b}}\times \frac{{{m}_{2}}}{{{M}_{2}}}\times \frac{1}{{{m}_{1}}}\]where \[{{m}_{2}}\]is mass of solute \[{{m}_{1}}\] is mass of solvent \[{{M}_{2}}\] molar mass of solute\[{{M}_{2}}=\frac{{{K}_{b}}\times {{m}_{2}}}{\Delta {{T}_{b}}{{m}_{1}}}\]
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