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JEE Main & Advanced Sample Paper JEE Main Sample Paper-4

  • question_answer
    3.92 g of ferrous ammonium sulphate (Mohr's salt) react completely with \[50\,mL\frac{N}{10}KMn{{O}_{4}}\] solution. The percentage purity of the sample is

    A)  50                         

    B)  78.4    

    C)  80                         

    D)  39.2

    Correct Answer: A

    Solution :

    Equation of KMn04 used \[=\frac{50\times 1}{100\times 10}=0.005\] \[\therefore \] Equation of Mohr's salt reacted \[=0.005\] \[\therefore \] Weight of Mohr's salt needed \[=0.005\times 392=1.96g\] Thus, percentage purity of Mohr's salt \[=\frac{1.96}{3.92}\times 100=50%\]


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