A) contradiction
B) tautology
C) equivalent to \[\tilde{\ }(p\Rightarrow q)\]
D) None of these
Correct Answer: D
Solution :
| P | q | \[\tilde{\ }q\] | \[p\wedge \tilde{\ }q\] | \[\tilde{\ }(p\wedge \tilde{\ }q)\] | \[p\to \tilde{\ }(p\wedge \tilde{\ }q)\] |
| T | F | T | T | F | F |
| F | T | F | F | T | T |
| \[\Rightarrow \] | |||||
| T | T | F | F | T | T |
| F | F | T | F | T | T |
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