2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-4

  • question_answer
    If period of \[{{\sin }^{2m}}\sqrt{k}x,m\in N\]is \[\pi ,\] then it \[\underset{n\to \infty }{\mathop{Lt}}\,{{k}^{n}}=\]

    A)  0                            

    B)  \[\infty \]      

    C)  1                            

    D)  None

    Correct Answer: C

    Solution :

    Period of \[{{\sin }^{2m}}=\frac{\pi }{\sqrt{k}}\] According to question,\[=\frac{\pi }{\sqrt{k}}=\pi \Rightarrow k=1\] \[\therefore \]\[\underset{n\to \infty }{\mathop{Lt}}\,{{k}^{n}}=\underset{n\to \infty }{\mathop{Lt}}\,{{1}^{n}}=1\]


You need to login to perform this action.
You will be redirected in 3 sec spinner