JEE Main & Advanced Sample Paper JEE Main Sample Paper-4

  • question_answer
    If \[\underset{n\to \infty }{\mathop{\lim }}\,\frac{\sum\limits_{r=1}^{n}{\sqrt{r}}\sum\limits_{r=1}^{n}{\frac{1}{\sqrt{r}}}}{\sum\limits_{r=1}^{n}{r}}=\frac{k}{3},\] then the value of k is

    A)  1                                            

    B)  4      

    C)  6                            

    D)  8

    Correct Answer: D

    Solution :

    \[\underset{n\to \infty }{\mathop{\lim }}\,\frac{\sum\limits_{r=1}^{n}{\sqrt{r}}\sum\limits_{r=1}^{n}{\frac{1}{\sqrt{r}}}}{\frac{n(n+1)}{2}}\underset{n\to ki}{\mathop{\lim }}\,\frac{\sum\limits_{r=1}^{n}{\sqrt{\frac{r}{n}}}\sum\limits_{r=1}^{n}{\frac{1}{\sqrt{\frac{r}{n}}}}}{\frac{{{n}^{2}}}{2}\left( 1+\frac{1}{n} \right)}\] \[=2\times \int\limits_{0}^{1}{\sqrt{x}}dx\int\limits_{0}^{1}{\frac{1}{\sqrt{x}}}dx\] \[=2\times \left[ \frac{{{x}^{3/2}}}{\frac{3}{2}} \right]_{0}^{1}\left[ \frac{{{x}^{1/2}}}{\frac{1}{2}} \right]_{0}^{1}=2\times \frac{2}{3}\times 2=\frac{8}{3}\] \[\therefore \]\[k=8\]


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