JEE Main & Advanced Sample Paper JEE Main Sample Paper-5

  • question_answer
    The interval of a for which (a, a2, a) and (3, 2,1) lies on same side of\[x+y-4z+2=0\]is

    A)  \[(\infty ,1]\cup (2,\infty ]\]      

    B)  \[[-\infty ,1)\cup [2,\infty )\]

    C)  \[(-\infty ,2]\cup (3,\infty ]\]    

    D)  \[(-\infty ,2)\cup [3,\infty )\]

    Correct Answer: A

    Solution :

     Here, it is given that (a, a2, a) and (3, 2, 1) lies on same side of x. + y - 4z + 2 = 0 \[\therefore \] (a + a2-4a + 2) (3 + 2 - 4 + 2) > 0 \[\Rightarrow \]                               \[({{a}^{2}}-3a+2)>0\]                                 \[(a-1)(a-2)>0\]                                 \[a\in (-\infty ,1]\cup (2,\infty ]\]


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