A) Iodoform test
B) Carbylamine test
C) Phthalein test
D) Ceric ammonium nitrate
Correct Answer: A
Solution :
The compounds containing \[-COC{{H}_{3}}\]group or \[-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{OH} \end{smallmatrix}}{\mathop{\text{CH}}}\,-\text{C}{{\text{H}}_{\text{3}}}\]group shows positive iodoform test. In between \[FC{{H}_{3}}OH\] and H\[\left( C{{H}_{3}}-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{OH} \end{smallmatrix}}{\mathop{\text{CH}}}\,-C{{H}_{3}} \right),\]only H contains \[\left( -\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{OH} \end{smallmatrix}}{\mathop{\text{CH}}}\,-C{{H}_{3}} \right)\] group. Thus, it gives positive iodoform test. Hence, F and H are distinguish by iodoform test.You need to login to perform this action.
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