A) 248.8 kJ of energy is evolved when reaction is proceeded at 1 atm pressure and 298 K temperature.
B) 248.8 kJ of energy is evolved irrespective of reaction conditions (pressure and temperature).
C) the reaction \[2{{H}_{2}}+{{O}_{2}}\xrightarrow[{}]{{}}2{{H}_{2}}O\] evolves same amount of energy 248.8 kJ
D) The reaction is \[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow[{}]{{}}{{H}_{2}}O(l)\]
Correct Answer: B
Solution :
Enthalpy change is a state function, its value doesn't depend on the intermediate conditions or path followed, it is the difference of energy of reactants and products present at 1 atmosphere and 298 K.You need to login to perform this action.
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