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JEE Main & Advanced Sample Paper JEE Main Sample Paper-8

  • question_answer
    When \[{{N}_{2}}{{O}_{5}}\] is heated at temp. T, it dissociates as\[{{N}_{2}}{{O}_{5}}(g)\rightleftharpoons {{N}_{2}}{{O}_{3}}(g)+{{O}_{2}}(g),\]\[{{K}_{c}}=2.5.\]At the same time \[{{N}_{2}}{{O}_{3}}\]decomposes as \[{{N}_{2}}{{O}_{3}}(g)\rightleftharpoons {{N}_{2}}O(g)+{{O}_{2}}(g).\] If initially 4.0 moles of \[{{N}_{2}}{{O}_{5}}\] are taken in 2.0 litre flask and allowed to attain equilibrium, concentration of \[{{O}_{2}}\] was formed to be 2.5M. Equilibrium concentration of \[{{N}_{2}}O\] is -

    A)  2.0                        

    B)  1.0

    C)  0.334                   

    D)  None of these

    Correct Answer: B

    Solution :

     \[co{{n}^{n}}at\,e{{q}^{m}}\]  \[\underset{2-x}{\mathop{{{N}_{2}}{{O}_{5}}}}\,(g)\underset{x-y}{\mathop{{{N}_{2}}{{O}_{3}}}}\,(g)+\underset{x+y}{\mathop{{{O}_{2}}(g)}}\,\] \[co{{n}^{n}}at\,e{{q}^{m}}\] \[\underset{x-y}{\mathop{{{N}_{2}}{{O}_{3}}}}\,(g)\underset{y}{\mathop{{{N}_{2}}O}}\,(g)+\underset{y+x}{\mathop{{{O}_{2}}(g)}}\,\] \[2.5=\frac{2.5\times (x-y)}{(2-x)}\] \[x-y=2-x\]or\[2x-y=2\And \]as per given \[[{{O}_{2}}(g)]=x+y=2.5\]\[x=1.5\]and\[[{{N}_{2}}O(g)]=y=1.0\]


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